(64-x^2)/(x^2+8x)=1

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Solution for (64-x^2)/(x^2+8x)=1 equation: 


D( x )

x^2+8*x = 0

x^2+8*x = 0

x^2+8*x = 0

x^2+8*x = 0

DELTA = 8^2-(0*1*4)

DELTA = 64

DELTA > 0

x = (64^(1/2)-8)/(1*2) or x = (-64^(1/2)-8)/(1*2)

x = 0 or x = -8

x in (-oo:-8) U (-8:0) U (0:+oo)

(64-x^2)/(x^2+8*x) = 1 // - 1

(64-x^2)/(x^2+8*x)-1 = 0

x^2+8*x = 0

x^2+8*x = 0

x*(x+8) = 0

x+8 = 0 // - 8

x = -8

x*(x+8) = 0

(64-x^2)/(x*(x+8))-1 = 0

(64-x^2)/(x*(x+8))+(-1*x*(x+8))/(x*(x+8)) = 0

64-1*x*(x+8)-x^2 = 0

64-2*x^2-8*x = 0

64-2*x^2-8*x = 0

2*(32-x^2-4*x) = 0

32-x^2-4*x = 0

DELTA = (-4)^2-(-1*4*32)

DELTA = 144

DELTA > 0

x = (144^(1/2)+4)/(-1*2) or x = (4-144^(1/2))/(-1*2)

x = -8 or x = 4

2*(x+8)*(x-4) = 0

(2*(x+8)*(x-4))/(x*(x+8)) = 0

(2*(x+8)*(x-4))/(x*(x+8)) = 0 // * x*(x+8)

2*(x+8)*(x-4) = 0

( x+8 )

x+8 = 0 // - 8

x = -8

( x-4 )

x-4 = 0 // + 4

x = 4

x in { -8} 

x = 4

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